4) Дано: AC = BC, AB = 6 дм., OD = 4 дм.
AD = 1/2AB = 1/2 * 6 = 3 дм.
R = CO = AO = BO
По т. Пифагора
R =√(OD^2 + AD^2) = √(4^2 + 3^2) = √(16 + 9) = √25 = 5 дм.
CD = CO + OD = 4 + 5 = 9 дм.
S△ABC = 1/2AB * CD =1/2 * 6 * 9 = 27 дм^2.
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Answers & Comments
4) Дано: AC = BC, AB = 6 дм., OD = 4 дм.
AD = 1/2AB = 1/2 * 6 = 3 дм.
R = CO = AO = BO
По т. Пифагора
R =√(OD^2 + AD^2) = √(4^2 + 3^2) = √(16 + 9) = √25 = 5 дм.
CD = CO + OD = 4 + 5 = 9 дм.
S△ABC = 1/2AB * CD =1/2 * 6 * 9 = 27 дм^2.