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khlmtvsl
@khlmtvsl
August 2022
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выполните решение (0,12а^n+2 b^n+2) : (-0,6a^n-1 b^n-1)
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179Валерон179
0,12a^n+2 b^n+2 : (-0.6a^n-1 b^-1)=0,12a^n+2 b^n+2\-0.6a^n-1 b^n-1 = 0,12a^n+2-(n-1) b^n+2\-0,6b^n-1 = 0,12a^n+2-n+1 b^n+2\-0,6b^n-1 = 0,12a^0+2+1 b^n+2\-0,6 b^n-1 = 0,12a^3 b^n+2\-0,6^n-1 = 0,12\-0,6 a^3 b^n+2-(n-1) = 0,12\-0,6 a^3 b^n+2-n+1 = 0,12\-0,6 a^3 b^0+2+1 = - 0,12\0,6 a^3 b^3 = -0,2a^3 b^3
Надеюсь помогла)
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Надеюсь помогла)