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lia0404
@lia0404
December 2021
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Выполните умножение :
1) (3x+y) (9x²- 3xy + y²)
2) (1-x²) (1+x²+x⁴)
3) (0,3a²+10) (0,09a⁴- 3a² + 100)
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Universalka
Verified answer
(3x + y)(9x² - 3xy + y²) = (3x)³ + y³ = 27x³ + y³
(1 - x²)(1 + x² + x⁴) = 1³ - (x²)³ = 1 - x⁶
(0,3a² + 10)(0,09a⁴ - 3a² + 100) = (0,3a²)³ + 10³ = 0,027a⁶ + 1000
1 votes
Thanks 1
123yui
1) получится
27х^3-9х^2у+3ху^2+9х^2у-3ху^2+у^3=27х^3+у^3
2) 1+х^2+х^4-х^2-х^4-х^6= 1-х^6
3)0,027а^6-0,9а^4+30а^2+0,9а^4-30а^2+1000=0,027а^6+1000
(^)-это степень
1 votes
Thanks 0
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Answers & Comments
Verified answer
(3x + y)(9x² - 3xy + y²) = (3x)³ + y³ = 27x³ + y³(1 - x²)(1 + x² + x⁴) = 1³ - (x²)³ = 1 - x⁶
(0,3a² + 10)(0,09a⁴ - 3a² + 100) = (0,3a²)³ + 10³ = 0,027a⁶ + 1000
27х^3-9х^2у+3ху^2+9х^2у-3ху^2+у^3=27х^3+у^3
2) 1+х^2+х^4-х^2-х^4-х^6= 1-х^6
3)0,027а^6-0,9а^4+30а^2+0,9а^4-30а^2+1000=0,027а^6+1000
(^)-это степень