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AcorN12
@AcorN12
August 2022
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Выполните умножения:
(2m^-n)(m+n)
(3n^-n-2)(n^+2n-5)
Разложите:
(m-8n)(3m-4n)-2n(3m-4n)
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Answers & Comments
evvoronina1
(2m^2- n)(m+n) = 2m^3 - mn + 2mn^2 - n^2
(3n^2 - n - 2)(n^2 + 2n -5) =
= 3n^4 - n^3 - 2n^2 + 6n^3 - 2n^2 - 4n - 15n^2 + 5n + 10 =
= 3n^4 -5n^3 - 19n^2 + n + 10
(m - 8n)(3m - 4n) -2n(3m - 4n) =
= (3m-4n)(m - 7n -2n) = (3m-4n)(m-9n)
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Answers & Comments
(3n^2 - n - 2)(n^2 + 2n -5) =
= 3n^4 - n^3 - 2n^2 + 6n^3 - 2n^2 - 4n - 15n^2 + 5n + 10 =
= 3n^4 -5n^3 - 19n^2 + n + 10
(m - 8n)(3m - 4n) -2n(3m - 4n) =
= (3m-4n)(m - 7n -2n) = (3m-4n)(m-9n)