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dahamitrackova
@dahamitrackova
September 2021
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Выражение -5а(2а+3)-(3-2а)
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ndehost
-5а(2а+3)-(3-2а)=-10a^2-15a-3+2a=-10a^2-13a-3 | *(-1)
10a^2+13a+3=0
D=13^2-4*3*10=169-120=49
x1=(-13-
√(49) )/(2*10)=-20/20=-1
x2=(-13+√(49) )/(2*10)=-6/20=-3/10
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Answers & Comments
10a^2+13a+3=0
D=13^2-4*3*10=169-120=49
x1=(-13-√(49) )/(2*10)=-20/20=-1
x2=(-13+√(49) )/(2*10)=-6/20=-3/10