3) y=1/x³⇒x=1/³√y; y=1/³√x⇒x=1/y³;
4) y=x^(3/5)⇒x=y^(5/3); y=x^(5/3)⇒x=y^(3/5).
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3) y=1/x³⇒x=1/³√y; y=1/³√x⇒x=1/y³;
4) y=x^(3/5)⇒x=y^(5/3); y=x^(5/3)⇒x=y^(3/5).