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semarassypnov
@semarassypnov
June 2022
1
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выразите а из равенства
а+7в=0
3а - 6в + 5 = 0
2в - 7а + 11 = 0
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leraT1
1)а+7в=0
а=-7в
2)3а-6в+5=0
3а=6в-5
а= (6в-5)/3
3)2в-7а+11=0
-7а=-11-2в
7а=11-2в
а=(11-2в)/7
1 votes
Thanks 7
semarassypnov
спасибо
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Answers & Comments
а=-7в
2)3а-6в+5=0
3а=6в-5
а= (6в-5)/3
3)2в-7а+11=0
-7а=-11-2в
7а=11-2в
а=(11-2в)/7