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onefourthree
@onefourthree
July 2022
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высота BD треугольника ABC равна 8 см и делит сторону АС на отрезки равные 4 и 5 см. Найдите площадь треугольника
с рисунком пожалуйста
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lvv9136
Ответ:
S=АC*DВ/2=8*(4+5)/2=36 см2
Объяснение:
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Answers & Comments
Ответ:
S=АC*DВ/2=8*(4+5)/2=36 см2
Объяснение: