Verified answer

Дано:

w (C) = 14,12%

w (Cl) =

83,53%

D(возд) =

2,93

Найти:

CxHyClz

Решение:

w

(H) = 100% - w (Cl + C) = 100% - (83,53 + 14,12%) = 2,35%

Mr

(в-ва) = 2,93∙ 29 = 85

n (э) = w(э) ∙ Mr(в-ва) \Ar(э) ∙ 100%

n (C) = 14,12%

∙ 85 \12 ∙ 100% = 1

n (Cl) =

83,53% ∙ 85 \35,5 ∙ 100% = 2

n (H) = 2,35%

∙ 85\1 ∙ 100% = 2

n (C) : n

(H) : n (CL)  = 1:2:2 = CxHyClz =  С1H2Cl2

ответ: С1H2Cl2

–  дихлорметан