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eden23
@eden23
July 2022
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вывести формулу аммиака если в его состав входит 82.36% азота 17.64% водорода
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gorshckowashur1
Ответ:
W(х/э)=(n*Aтм(х/э)*100%):Mr(вва)
82,36%*Mr=14*1*100%
mr=140000/8236
Mr=16,99
Mr=17
NH3
Mr(NH3)=14+3*1=14+3=17
4 votes
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Answers & Comments
W(х/э)=(n*Aтм(х/э)*100%):Mr(вва)
82,36%*Mr=14*1*100%
mr=140000/8236
Mr=16,99
Mr=17
NH3
Mr(NH3)=14+3*1=14+3=17