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ewwe123456
@ewwe123456
July 2022
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Вывести химическую формулу однозамещённого хлорпроизводного предельного углеводорода, если его относительная плотность по воздуху равна 2,224.
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UlugbekRakhimov
Verified answer
M= D* M(vozdux)= 2.224*29= 64.5
64.5-35(M(Cl))=29M(CxHx)
C2H5Cl
3 votes
Thanks 7
UlugbekRakhimov
metodom podbora
ewwe123456
а по другому никак?
UlugbekRakhimov
spomnil. v etom slechaye mojno ispilzovat uravneniye 12x + 2x+1=29
withoutmonday
M=D*Mв=2.224*29=64.5
withoutmonday
M(CxHy)=64.5-35.5=29
withoutmonday
12x+2x+1=29
withoutmonday
14x=28
withoutmonday
x=2=n(C)
withoutmonday
n(H)=29-24=5
withoutmonday
полное решение
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Answers & Comments
Verified answer
M= D* M(vozdux)= 2.224*29= 64.564.5-35(M(Cl))=29M(CxHx)
C2H5Cl