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muhin12
@muhin12
July 2022
2
1
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ω (соли) - 35%
m (раствора) - 400г
m2 (H2O) - 100г
ω2 (cоли) - ?
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9856565651
W1m1=x(m1+mH2O)
35%*400г=х(400г+100г)
14000=500х
х=14000/500=28%
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ketrin9999
трошки запутано) але як кому
9856565651
Сори, я не понимаю ваш язык )
ketrin9999
M(солі в розчині) = 400 * 0,35 = 140г
m(розчину 2) = 400 +100 = 500г
W2 (солі) = 140/500 = 0,28 або 28%
0 votes
Thanks 0
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Answers & Comments
35%*400г=х(400г+100г)
14000=500х
х=14000/500=28%
m(розчину 2) = 400 +100 = 500г
W2 (солі) = 140/500 = 0,28 або 28%