Home
О нас
Products
Services
Регистрация
Войти
Поиск
muhin12
@muhin12
July 2022
2
4
Report
ω (соли) - 35%
m (раствора) - 400г
m2 (H2O) - 100г
ω2 (cоли) - ?
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
9856565651
W1m1=x(m1+mH2O)
35%*400г=х(400г+100г)
14000=500х
х=14000/500=28%
0 votes
Thanks 0
ketrin9999
трошки запутано) але як кому
9856565651
Сори, я не понимаю ваш язык )
ketrin9999
M(солі в розчині) = 400 * 0,35 = 140г
m(розчину 2) = 400 +100 = 500г
W2 (солі) = 140/500 = 0,28 або 28%
0 votes
Thanks 0
×
Report "ω (соли) - 35% m (раствора) - 400г m2 (H2O) - 100г ω2 (cоли) - ?..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
35%*400г=х(400г+100г)
14000=500х
х=14000/500=28%
m(розчину 2) = 400 +100 = 500г
W2 (солі) = 140/500 = 0,28 або 28%