ω=80 L=125 C=?
ω=1/√(L*C) C=1/(ω²*L)=1/(80²*125)=1.25*10^-6 (1.25 мкФ)
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ω=80 L=125 C=?
ω=1/√(L*C) C=1/(ω²*L)=1/(80²*125)=1.25*10^-6 (1.25 мкФ)
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