M(Fe(OH)2)= 56 + 32 + 2 = 90 g/mol
M(Fe(OH)3)= 56 + 48 + 3 = 107 g/mol
m(Fe(OH)2)= 90*2 = 180 g
m(Fe(OH)3)= 107*2 = 214 g
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M(Fe(OH)2)= 56 + 32 + 2 = 90 g/mol
M(Fe(OH)3)= 56 + 48 + 3 = 107 g/mol
m(Fe(OH)2)= 90*2 = 180 g
m(Fe(OH)3)= 107*2 = 214 g