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МоЕсТрО15
@МоЕсТрО15
September 2021
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w(O в H3P04) определите массовую долю кислорода в фосфорной кислоте
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mrvladimir2
Verified answer
Mr(H3PO4)=3Ar(H)+Ar(P)+4Ar(O) = 3+31+64=98
ω(O)=64/98*100% = 65,31%
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Verified answer
Mr(H3PO4)=3Ar(H)+Ar(P)+4Ar(O) = 3+31+64=98ω(O)=64/98*100% = 65,31%