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alenkinalina
@alenkinalina
August 2021
1
9
Report
x 1 2 3 4 5
p
0,3
0,3
0,1
0,1
0,2
Найти: 1) математическое
ожидание М (X);
2) дисперсию
D(X);
3) среднее квадратическое
отклонение σ.
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Answers & Comments
nelle987
Verified answer
M(X) = 0.3 * 1 + 0.3 * 2 + 0.1 * 3 + 0.1 * 4 + 0.2 * 5 = 2.6
M(X^2) = 0.3 * 1 + 0.3 * 4 + 0.1 * 9 + 0.4 * 16 + 0.2 * 25 = 13.8
D(X) = M(X^2) - (M(X))^2 = 13.8 - 2.6^2 = 7.04
σ = sqrt(D(X)) ~ 2.65
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Answers & Comments
Verified answer
M(X) = 0.3 * 1 + 0.3 * 2 + 0.1 * 3 + 0.1 * 4 + 0.2 * 5 = 2.6M(X^2) = 0.3 * 1 + 0.3 * 4 + 0.1 * 9 + 0.4 * 16 + 0.2 * 25 = 13.8
D(X) = M(X^2) - (M(X))^2 = 13.8 - 2.6^2 = 7.04
σ = sqrt(D(X)) ~ 2.65