f(x) = x²-3x+2/x-1 = x²-2x-x+2/x-1 = x(x-2)-(x-2)/x-1 = (x-1)(x-2)/x-1 = x-2[x ≠ 1]
f(3) = 3-2 = 1
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f(x) = x²-3x+2/x-1 = x²-2x-x+2/x-1 = x(x-2)-(x-2)/x-1 = (x-1)(x-2)/x-1 = x-2[x ≠ 1]
f(3) = 3-2 = 1