По теореме Виета:
[tex]{x}^{2} + bx + c = 0\\ x_{1} + x_{2} = - b[/tex]
[tex] {x}^{2} - 10x + 3 = 0 \\ x_{1} + x_{2} = - ( - 10) = 10 [/tex]
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По теореме Виета:
[tex]{x}^{2} + bx + c = 0\\ x_{1} + x_{2} = - b[/tex]
[tex] {x}^{2} - 10x + 3 = 0 \\ x_{1} + x_{2} = - ( - 10) = 10 [/tex]