Verified answer

Ответ:

xє (4/7,11) U (11, +  бескінечності)

Объяснение:

[tex]\left \{ {{|x-11| > 0} \atop {7x-4 > 0}} \right. \\\left \{ {{|x-11| < 0} \atop {7x-4 < 0}} \right. \\\\\left \{ {{x e R/(11)} \atop {x > \frac{7}{4}}} \right. \\\\\\\left \{ {{} \atop {x < \frac{4}{7}}} \right. \\\\[/tex]

xє (4/7,11) U (11, +  бескінечності)