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srgjjkungurv
@srgjjkungurv
July 2022
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(6x- x^2-6 )/(x-1)- (2x-3)/(x-1)=1
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annamogera
(6x- x^2-6-2х+3)/(х-1)=1
- x^2+4х-3=х-1
-х^2+3х-2=0
Д=1
х1=2;
х2=1-посторонний корень,т.к. он обращает знамегатель в 0.
Ответ: 2
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Answers & Comments
- x^2+4х-3=х-1
-х^2+3х-2=0
Д=1
х1=2;
х2=1-посторонний корень,т.к. он обращает знамегатель в 0.
Ответ: 2