Найти область определения функции: y = √(5x - 2x^2) y = - (4/(x-1)^2) Огромное спасибо. Created by vlad5kd. algebra-ru

(x-1)^2) Огромное спасибо...

vlad5kd @vlad5kd

August 2022 1 12 Report

Найти область определения функции:
y = √(5x - 2x^2)

y = - (4/(x-1)^2)

Огромное спасибо

Answers & Comments

arsenlevadniy

Verified answer

$y = \sqrt{5x - 2x^2}, \\ 
5x - 2x^2 \geq 0, \\
-2x(x-2,5) \geq 0, \\ 
x(x-2,5) \leq 0, \\
0 \leq x \leq 2,5, \\ 
D_y=[0;2,5];$

$y=-\frac{4}{(x-1)^2}, \\ 
(x-1)^2 \neq 0, \\ 
x-1 \neq 0, \\
x \neq 1, \\
D_y=(-\infty;1)\cup(1;+\infty).$

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