Помогите пожалуйста решить пределы, срочно!!!!!!!!!
1)lim 1-cosx/x²
x→0
2) lim arctg7x(e^2x -1)
x→0
3) lim 2+∛x+2/x+10
x→-10
4) lim x²-5x+6/x²-12x+20
x→2
1)lim 1-cosx/x²
x→0
2) lim arctg7x(e^2x -1)
x→0
3) lim 2+∛x+2/x+10
x→-10
4) lim x²-5x+6/x²-12x+20
x→2
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Answers & Comments
1)lim (1-cosx)/x² = lim 2sin²(x/2) / 4(x/2)²=lim (1/2) sin²(x/2) / (x/2)²=
=(1/2) * lim sin(x/2) / (x/2) * lim sin(x/2) / (x/2) = (1/2)*1*1=1/2
2) lim (arctg7x)(e^2x -1)=arctg0 * (1-1)=0*0=0
3) lim 2+∛x+2/x+10=2-∛10-2/10+10=11,8-∛10
4) lim x²-5x+6/x²-12x+20 = 4-5*2+6/4-12*2+20=4-10+1,5-24+20=-8,5