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kirbina2016
@kirbina2016
July 2022
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Найдите значение производной функции f
1 ) f(x)=cos x * sinx, x0=п/6
2) f(x)=4/x-12x^5. x0=1
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mrctas57
1. f'(x) = - sinx*sinx+cosx*cosx.
При х0= п/6: - 1/2*1/2+(корень из 3)/2*(корень из 3)/2=-1/4+3/4=2/4=1/2
2.f'(x) = (x-4)/x^2 - 60*x^4. При х0=1:
-3-60=-63
2 votes
Thanks 4
kirbina2016
капец ты умный)
mrctas57
Спасибо)
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Answers & Comments
При х0= п/6: - 1/2*1/2+(корень из 3)/2*(корень из 3)/2=-1/4+3/4=2/4=1/2
2.f'(x) = (x-4)/x^2 - 60*x^4. При х0=1:
-3-60=-63