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Аффтапелод
@Аффтапелод
July 2022
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Найдите производную функции:
1) f(x)=(2x+3)/(3x+5);
2) f(x)=(x+3)/(x-1).
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sedinalana
Verified answer
1) f(x)=(2x+3)/(3x+5);
f`(x=[(2x+3)`*(3x+5)-(3x+5)`(2x+3)]/(3x+5)
²=[2(3x+5)-3(2x+3)]/(3x+5)²=
=(6x+10-6x-9)/(3x+5)
²=1/(3x+5)²
2) f(x)=(x+3)/(x-1).
f`(x)=[1*(x-1)-1*(x+3)]/(x-1)
²=(x-1-x-3)/(x-1)²=-4/(x-1)²
1 votes
Thanks 4
Аффтапелод
Огромное Вам спасибо. =)
Reshallka
Verified answer
Решение на фото
Удачи;)
1 votes
Thanks 2
Аффтапелод
Спасибо Вам. ;)
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Answers & Comments
Verified answer
1) f(x)=(2x+3)/(3x+5);f`(x=[(2x+3)`*(3x+5)-(3x+5)`(2x+3)]/(3x+5)²=[2(3x+5)-3(2x+3)]/(3x+5)²=
=(6x+10-6x-9)/(3x+5)²=1/(3x+5)²
2) f(x)=(x+3)/(x-1).
f`(x)=[1*(x-1)-1*(x+3)]/(x-1)²=(x-1-x-3)/(x-1)²=-4/(x-1)²
Verified answer
Решение на фотоУдачи;)