f(x) = ln(x + 1)/(x-1)
f '(x) = (ln(x + 1)/(x-1))' = (x - 1)/(x + 1)·(-2/(x - 1)²) = -2/(x² - 1)
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f(x) = ln(x + 1)/(x-1)
f '(x) = (ln(x + 1)/(x-1))' = (x - 1)/(x + 1)·(-2/(x - 1)²) = -2/(x² - 1)