{ (x-1)в квадарате+(у-1)в квадрате=4 ;y=x
(x-1)²+(y-1)²=4; (1)
y=x; (2)
(x-1)²+(x-1)²=4;
x²-2x+1+x²-2x+1=4;
2x²-4x-2=0;
x²-2x-1=0;
D=4+4=8; √D=2√2;
x₁=1-√2;
x₂=1+√2;
y₁=1-√2;
y₂=1+√2.
Ответ: (1-√2; 1-√2), (1+√2; 1+√2).
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Answers & Comments
(x-1)²+(y-1)²=4; (1)
y=x; (2)
(x-1)²+(x-1)²=4;
x²-2x+1+x²-2x+1=4;
2x²-4x-2=0;
x²-2x-1=0;
D=4+4=8; √D=2√2;
x₁=1-√2;
x₂=1+√2;
y₁=1-√2;
y₂=1+√2.
Ответ: (1-√2; 1-√2), (1+√2; 1+√2).