Вычислить количество корней (х^2 – 1)(х^2 – 2х – 24)(9х^2 – 12х + 4) = 0 х^2 – 3х + 4/x-2 = 4/x-2 - 2. Created by kvast. algebra-ru

x-2 - 2...

July 2022 1 29 Report

Вычислить количество корней
(х^2 – 1)(х^2 – 2х – 24)(9х^2 – 12х + 4) = 0

х^2 – 3х + 4/x-2 = 4/x-2 - 2

Answers & Comments

m11m 1) (х²-1)(х²-2х-24)(9х²-12х+4)=0
х²-1=0 х²-2х-24=0 9х²-12х+4=0
(х-1)(х+1)=0 Д=4+24*4=4+96=100 (3х-2)²=0
х-1=0 х+1=0 х₃=(2-10)/2=-8/2=-4 3х-2=0
х₁=1 х₂=-1 х₄=12/2=6 3х=2
х₅=2/3
Ответ: 5 корней.
х₁=1 х₂=-1 х₃=-4 х₄=6 х₅=2/3

2) х²-3х+4 = 4 - 2
х-2 х-2
х≠2
х²-3х+4=4-2(х-2)
х²-3х+4=4-2х+4
х²-3х+2х+4-8=0
х²-х-4=0
Д=1+4*4=1+16=17
х₁=(1-√17)/2
х₂=(1+√17)/2
Ответ: 2 корня:
х₁=(1-√17)/2
х₂=(1+√17)/2

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kvast August 2022 | 0 Ответы

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