x^2+3x+2=(x+2)(x+1)
(1-x)/(x+2)(x+1)+(1-x)/(x+2)=0
(1-x)/(x+2)(1/(x+1)+1)=0
x1=1
1/(x+1)+1=0
(1+1+x)/(x+1)=0
x=-2
ОДЗ x≠-2; x≠-1
ответ х=1
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x^2+3x+2=(x+2)(x+1)
(1-x)/(x+2)(x+1)+(1-x)/(x+2)=0
(1-x)/(x+2)(1/(x+1)+1)=0
x1=1
1/(x+1)+1=0
(1+1+x)/(x+1)=0
x=-2
ОДЗ x≠-2; x≠-1
ответ х=1