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Батьок123
@Батьок123
July 2022
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Розв'язати нерівність методом інтервалів (x-1)(x+3)(x-4)/(x-2) БІЛЬШЕ РІВНЕ 0
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sedinalana
(x-1)(x+3)(x-4)/(x-2)≥0
x=1 x=-3 x=4 x=2
+ _ + _ +
---------------[-3]------------[1]---------------(2)-----------------[4]----------------
x∈(-∞;-3] U [1;2) U [4;∞)
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x=1 x=-3 x=4 x=2
+ _ + _ +
---------------[-3]------------[1]---------------(2)-----------------[4]----------------
x∈(-∞;-3] U [1;2) U [4;∞)