b(x)=x*(4-x)/(x-2)
b(4-x)=(4-x)(4-4+x)/(4-x-2)
b(4-x)=x*(4-x)/(2-x)
b(x)+b(4-x)=x(4-x)/(x-2)+x(4-x)/(2-x)=x(4-x)/(x-2)-x(4-x)/(x-2)=0
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Answers & Comments
b(x)=x*(4-x)/(x-2)
Сначала находим b(4-x):
b(4-x)=(4-x)(4-4+x)/(4-x-2)
b(4-x)=x*(4-x)/(2-x)
Тогда:
b(x)+b(4-x)=x(4-x)/(x-2)+x(4-x)/(2-x)=x(4-x)/(x-2)-x(4-x)/(x-2)=0
Ответ: 0