Ответ:
f(x)=(x³-5)/(x-2)
f'(x)=(x³-5)' * (x-2) - (x³-5) * (x-2)' /(x-2)^2 = 2x^3 - 6x^2 + 5 / (x-2)^2
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Ответ:
Verified answer
f(x)=(x³-5)/(x-2)
f'(x)=(x³-5)' * (x-2) - (x³-5) * (x-2)' /(x-2)^2 = 2x^3 - 6x^2 + 5 / (x-2)^2