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sveta2206
@sveta2206
July 2022
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(x-2)^2+(x-2y)^2=5
(x-2)^2-(x-2y)^2=-3
Решите систему уравнений
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19guljan72
(х-2)
²+(х-2у)²=5
(
х-2)²-(х-2у)²=-3
2(х-2)
²=2
(х-2)²=1
х=3,
1+(3-2у)²=5
(3-2у)²=5-1
(3-2у)²=4=2²
3-2у=2
-2у=2-3
-2у=-1
у=0,5
ответх=3,у=0,5
3 votes
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Answers & Comments
(х-2)²-(х-2у)²=-3
2(х-2)²=2
(х-2)²=1
х=3,
1+(3-2у)²=5
(3-2у)²=5-1
(3-2у)²=4=2²
3-2у=2
-2у=2-3
-2у=-1
у=0,5
ответх=3,у=0,5