lim x²-8+15/x²-25 x->5. Created by ksenia19991999. matematika-ru

x²-25 x->5...

Support001 $\lim_{x \to 5} \frac{x^2-8x+15}{x^2-5^2}= \frac{0}{0} = \\
x^2-8x+15=0 ; D=64-4*15=4 ; x_{1,2} = \frac{8+-2}{2} ; x_1 = 5 ; x_2 = 3 \\
 \lim_{x \to 5} \frac{(x-5)(x-3)}{(x-5)(x+5)} = 2/10=1/5 = 0,2 \\
$
Лопиталь:
lim (x^2-8x+15)/(x^2-25) = lim (2x-8)/2x=10-8/10=2/10 = 0,2
x>5

1 votes Thanks 1

harutyunyan46 Lim (x^2 -8x +15 )/ x^2-25 =lim (x-5)* (x-3)/(x-5)*(x+5) = lim(x-3)/(x+5 ) = x->5 x->5 x->5 = (5-3)/(5+5)= 2/10 = 0.2 . ответ ; 0.2

1 votes Thanks 1

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