D=b²-4ac=(-2)²-4×1×(-3)=4+12=16
x1=-b±√D/2a=2-4/2=-1
x2=2+4/2=3
Ответ: x1=-1,x2=3
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D=b²-4ac=(-2)²-4×1×(-3)=4+12=16
x1=-b±√D/2a=2-4/2=-1
x2=2+4/2=3
Ответ: x1=-1,x2=3