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Ответ:

a)x-2x²=0

x*(1-2x)=0

[tex]x = 0 \\ 1 - 2x = 0[/tex]

[tex]1 - 2x = 0 \\ - 2x = - 1 \\ \div - 2 \\ x = \frac{1}{2} [/tex]

[tex]x = 0 \\ x = \frac{1}{2} [/tex]

[tex] x_{1} = 0. x_{2} = \frac{1}{2} [/tex]

б)2x²+8x=0

2x*(x+4)=0|:2

x*(x+4)=0

[tex]x = 0 \\ x + 4 = 0[/tex]

[tex]x + 4 = 0 \\ x + 4 - 4 = 0 - 4 \\ x = - 4[/tex]

[tex]x = 0 \\ x = - 4[/tex]

[tex] x_{1} = - 4. x_{2} = 0[/tex]

Надіюсь допомогла)))