x ^3 + 3x²- 2x - 6 = 0
х²(х+3)-2(х+3)=0
(х+3)(х²-2)=0
х₁+3=0 х₁=-3
х²-2=0 х₂=√2 х₃=-√2
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x ^3 + 3x²- 2x - 6 = 0
х²(х+3)-2(х+3)=0
(х+3)(х²-2)=0
х₁+3=0 х₁=-3
х²-2=0 х₂=√2 х₃=-√2