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ElbekXD
@ElbekXD
August 2022
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(x-3)^4+(x-3)^2-12=0
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MizoriesKun
(x-3)^4+(x-3)^2-12=0 замена (x-3)²=a a≥0
a²+a-12=0
D=1+48=49
a₁=(-1+7)/2=3 (x-3)²=3 (x-3)=+/-√3
х₁= 3+√3 ; х₂= 3-√3
a₂= (-1-7)/2= -4 не подходит под ОДЗ
5 votes
Thanks 8
mukus13
только при замене a>=0 должно быть )
MizoriesKun
поправила ))
mukus13
спасибо )
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Answers & Comments
a²+a-12=0
D=1+48=49
a₁=(-1+7)/2=3 (x-3)²=3 (x-3)=+/-√3 х₁= 3+√3 ; х₂= 3-√3
a₂= (-1-7)/2= -4 не подходит под ОДЗ