Verified answer

Ответ:

(x-3)² (x-2)=12(x-3)

(x-3)² (x-2)-12(x-3) = 0

(x-3) ((x-3)(x-2) -12 ) = 0

(х-3)(х²-2х-3х+6-12)=0

(x-3)(x²-5x-6 )= 0

x-3=0 і х²-5х-6=0

х1=3 і х2=-1, х3=6

Сума= 8