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adamenkosasha83
@adamenkosasha83
July 2023
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Знайдіть проміжки спадання функції у = x²-3x2+3
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Аккаунт удален
у=х^2-3
а=1,б=0
х=-0/2•1
х=0
у=х^2-3•2+3
у=-3
(0,-3)
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Answers & Comments
а=1,б=0
х=-0/2•1
х=0
у=х^2-3•2+3
у=-3
(0,-3)