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dashaplyusch
@dashaplyusch
October 2021
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√(x-5) + √(10-x) < 3
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abror6
-/(x-5)^2<(3--/(10-x))^2
x-5 < 9-6-/10-x)+10-x
x-5 < 19-6-/10-x)-x
(6-/10-x)^2 < (24 - 2x ) ^2
36 (10-x)< 576-96x +4x
360- 36 x < 576 -92x
56x < 216
x < 216/56
x < 27/7
решил как смог !!!
1 votes
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Answers & Comments
x-5 < 9-6-/10-x)+10-x
x-5 < 19-6-/10-x)-x
(6-/10-x)^2 < (24 - 2x ) ^2
36 (10-x)< 576-96x +4x
360- 36 x < 576 -92x
56x < 216
x < 216/56
x < 27/7
решил как смог !!!