(x²-5x+23)(x+5)=(12+y)(y-12)=6x⁵+0,7b³)²=(3k-t)³=(x+4)²-x²(x+12)-5x=x+1 (теңдеу). Created by abzalabaev017.

(x²-5x+23)(x+5)=(12+y)(y-12)=6x⁵+0,7b³)²=(3k-t)³=(x+4)²-x²(x+12)-5x=x+1 (теңдеу)

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(x²-5x+23)(x+5)=
(12+y)(y-12)=
6x⁵+0,7b³)²=
(3k-t)³=
(x+4)²-x²(x+12)-5x=x+1 (теңдеу)

unira216

осыны дурыстап кошыр дурыстап тусыре алмадым

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