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дипсон228
@дипсон228
August 2021
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при каком значении а имеет 1 корень
x²-4x+3 / x-a
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btu27152
X^2+4x+a-3=0
D=0
16 - 4 * (a-3) =0
16 - 4a +12=0
4a=28
a=7
x^2+4x+7-3=x^2+4x+4=(x+2)^2=0 x=-2
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Answers & Comments
D=0
16 - 4 * (a-3) =0
16 - 4a +12=0
4a=28
a=7
x^2+4x+7-3=x^2+4x+4=(x+2)^2=0 x=-2