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ZHICH
@ZHICH
August 2022
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найдите координаты точек пересечения графиков функций y=6/x и y=x+1
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ПрофиЗнания
Verified answer
X+1=6/x
x2+x-6=0
D=1+24=25=5^2
x1=-1+5/2=4/2=2
x2=-1-5/2=-6/2=-3
y1=6/2=3
y2=6/(-3)=-2
8 votes
Thanks 10
novo51
Verified answer
Найдем решение системы этих уравнений
y=6/x и y=x+1
х+1 =
6/х *х
х^2 + x = 6
х^2 + x - 6 =0
D=b^2-4ac = 1 + 24 = 25
x1 = (-1-5)/2 = -6/2 = -3
x2 = (-1+5)/2 = 4/2 = 2
при x1 =-3 y1 = -3+1=-2
при x2 =2 y1 = 2+1=3
Ответ. (-3, -2), (2, 3).
3 votes
Thanks 4
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Answers & Comments
Verified answer
X+1=6/xx2+x-6=0
D=1+24=25=5^2
x1=-1+5/2=4/2=2
x2=-1-5/2=-6/2=-3
y1=6/2=3
y2=6/(-3)=-2
Verified answer
Найдем решение системы этих уравненийy=6/x и y=x+1
х+1 = 6/х *х
х^2 + x = 6
х^2 + x - 6 =0
D=b^2-4ac = 1 + 24 = 25
x1 = (-1-5)/2 = -6/2 = -3
x2 = (-1+5)/2 = 4/2 = 2
при x1 =-3 y1 = -3+1=-2
при x2 =2 y1 = 2+1=3
Ответ. (-3, -2), (2, 3).