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Kofigimun
@Kofigimun
July 2022
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√x <= x-1
Помогите решить, плез!
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mikael2
X≥0
√x≤x-1
x≤x²-2x+1 x²-3x+1≥0 D=9-4=5
x1=1/2[3-√5] =
1.5-√5/2
x2=
1.5+√5/2
---------------x1---------------------x2-----------------
+ - +
x∈(1.5+√5/2;∞)
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Kofigimun
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Answers & Comments
√x≤x-1
x≤x²-2x+1 x²-3x+1≥0 D=9-4=5
x1=1/2[3-√5] =1.5-√5/2
x2=1.5+√5/2
---------------x1---------------------x2-----------------
+ - +
x∈(1.5+√5/2;∞)