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Maryashc
@Maryashc
August 2022
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Найдите наибольшее значение функции y= (54-x^3)/x на отрезке [-9;-1]
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erzhan9210
У=54/х-х²
у'=-54/х²-2х=0
54+2х³=0
х³=-27
х=-3
у(-9)=(54-(-9)³)/(-9)=(54+729)/(-9)=783/(-9)=-87
у(-3)=(54-(-3)³)/(-3)=(54+27)/(-3)=81/(-3)=-27
у(-1)=(54-(-1)³)/(-1)=(54+1)/(-1)=-55
наименьшее у(-9)=-87
наибольшее у(-3)=-27
5 votes
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Answers & Comments
у'=-54/х²-2х=0
54+2х³=0
х³=-27
х=-3
у(-9)=(54-(-9)³)/(-9)=(54+729)/(-9)=783/(-9)=-87
у(-3)=(54-(-3)³)/(-3)=(54+27)/(-3)=81/(-3)=-27
у(-1)=(54-(-1)³)/(-1)=(54+1)/(-1)=-55
наименьшее у(-9)=-87
наибольшее у(-3)=-27