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davron96
@davron96
July 2022
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lim (x->0) (sin7x +sin3x)/x sinx
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ShirokovP
Verified answer
Получим неопределенность 0/0
Правило Лопиталя
lim x-> 0
(sin7x +sin3x) ' / (x sinx) ' =
=
lim x-> 0 (7cos7x + 3cos3x) / (sinx + x*cosx ) =
= (7cos7*0 + 3cos3*0) / (sin0 + 0*cos0 ) = 10/0 = ∞
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Answers & Comments
Verified answer
Получим неопределенность 0/0Правило Лопиталя
lim x-> 0 (sin7x +sin3x) ' / (x sinx) ' =
= lim x-> 0 (7cos7x + 3cos3x) / (sinx + x*cosx ) =
= (7cos7*0 + 3cos3*0) / (sin0 + 0*cos0 ) = 10/0 = ∞