Найдите произвольную функции y=ctg(ln((e^x+e^-x)/x)) Срочно!. Created by dream2016. algebra-ru

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x)) Срочно!...

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Найдите произвольную функции y=ctg(ln((e^x+e^-x)/x)) Срочно!

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natalyabryukhova

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$y=ctg ln\frac{e^x+e^-^x}{x}\\ \\y'=-\frac{1}{sin^2ln\frac{e^x+e^-^x}{x}}*\frac{1}{\frac{e^x+e^-^x}{x}}*\frac{(e^x+e^-^x*(-1))*x-(e^x+e^-^x)}{x^2}=-\frac{1}{sin^2ln\frac{e^x+e^-^x}{x}}*\frac{x}{e^x+e^-^x}* \frac{(e^x-e^-^x)*x-(e^x+e^-^x)}{x^2}$

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napishite sochinenie na odnu iz tem svet klyuchevoe slovo v russkoj literature put

iz 7 predlozheniya vypishite slovo kategorii sostoyaniya 7 net podumal arkadij

ukazhite ryad slov v kotorom vse prilagatelnye kachestvennye 1 dlinnaya reka hi

v srednem na 50 ispravnyh karmannyh fonarikov prihoditsya dva neispravnyh najdit

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