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Anastaisha14
@Anastaisha14
July 2022
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X в квадрате +(23-x)=17 в квадрате
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gorshckowashur1
Ответ:
x^2+23-x=17^2
x^2-x+23=289
x^2-x=289-23
x^2-x=266
x^2-x-266=0
D=1+266*4=1065
x1=1-_/1065/2
x2=1+_/1065/2
1 votes
Thanks 1
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Answers & Comments
x^2+23-x=17^2
x^2-x+23=289
x^2-x=289-23
x^2-x=266
x^2-x-266=0
D=1+266*4=1065
x1=1-_/1065/2
x2=1+_/1065/2