y = f(x), f(x) = 1/x
=> f(x + 2) = 1/(x + 2)
f(x + 8) = 1/(x + 8)
По условию f(x + 2) = 9(x + 8), тогда:
1/(x + 2) = 9/(x + 8), x ≠ -2, x ≠ -8
9*(x + 2) = x + 8
9x + 18 = x + 8
9x - x = 8 - 18
8x = -10
x = -10/8 = -5/4 = -1 1/4
Ответ: -1 1/4.
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
f(x+8)=1/(x+8)
Т.к f(x+2)=9f(x+8), то
Ответ : при х= -1,25
y = f(x), f(x) = 1/x
=> f(x + 2) = 1/(x + 2)
f(x + 8) = 1/(x + 8)
По условию f(x + 2) = 9(x + 8), тогда:
1/(x + 2) = 9/(x + 8), x ≠ -2, x ≠ -8
9*(x + 2) = x + 8
9x + 18 = x + 8
9x - x = 8 - 18
8x = -10
x = -10/8 = -5/4 = -1 1/4
Ответ: -1 1/4.