Verified answer

Ответ:

x≈19.92

y≈25.61

Объяснение:

∠QRM=180°-∠MRL=180°-80°=100°

∠M=180°-∠Q-∠QRM=180°-50°-100°=30°

Применяем теорему синусов:

[tex]\frac{QR}{\sin \angle M} =\frac{QM}{\sin \angle QRM} =\frac{LM}{\sin \angle Q} \\ \\ 1) \ \frac{13}{\sin 30^\circ} =\frac{y}{\sin 100^\circ} \\ \\ y=\frac{13*\sin 100^\circ}{\sin 30^\circ}= \frac{13*\sin 100^\circ}{\frac{1}{2} }=26\sin 100^\circ \approx 25.61[/tex]

[tex]2) \ \frac{13}{\sin 30^\circ} =\frac{x}{\sin 50^\circ} \\ \\ x=\frac{13*\sin 50^\circ}{\sin 30^\circ}= \frac{13*\sin 50^\circ}{\frac{1}{2} }=26\sin 50^\circ \approx 19.92[/tex]